Base | Representation |
---|---|
bin | 10011000111001101011… |
… | …110111001010011100010 |
3 | 11122120010222020200122222 |
4 | 103013031132321103202 |
5 | 133004332042003402 |
6 | 2443212351031042 |
7 | 163614404436554 |
oct | 23071536712342 |
9 | 4576128220588 |
10 | 1313412453602 |
11 | 4670190a9097 |
12 | 19266b20b482 |
13 | 96b14a7b012 |
14 | 477d89db4d4 |
15 | 2427169a7a2 |
hex | 131cd7b94e2 |
1313412453602 has 4 divisors (see below), whose sum is σ = 1970118680406. Its totient is φ = 656706226800.
The previous prime is 1313412453589. The next prime is 1313412453623. The reversal of 1313412453602 is 2063542143131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1202182866481 + 111229587121 = 1096441^2 + 333511^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 328353113399 + ... + 328353113402.
Almost surely, 21313412453602 is an apocalyptic number.
1313412453602 is a deficient number, since it is larger than the sum of its proper divisors (656706226804).
1313412453602 is an equidigital number, since it uses as much as digits as its factorization.
1313412453602 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 656706226803.
The product of its (nonzero) digits is 51840, while the sum is 35.
Adding to 1313412453602 its reverse (2063542143131), we get a palindrome (3376954596733).
The spelling of 1313412453602 in words is "one trillion, three hundred thirteen billion, four hundred twelve million, four hundred fifty-three thousand, six hundred two".
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