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1313412453602 = 2656706226801
BaseRepresentation
bin10011000111001101011…
…110111001010011100010
311122120010222020200122222
4103013031132321103202
5133004332042003402
62443212351031042
7163614404436554
oct23071536712342
94576128220588
101313412453602
114670190a9097
1219266b20b482
1396b14a7b012
14477d89db4d4
152427169a7a2
hex131cd7b94e2

1313412453602 has 4 divisors (see below), whose sum is σ = 1970118680406. Its totient is φ = 656706226800.

The previous prime is 1313412453589. The next prime is 1313412453623. The reversal of 1313412453602 is 2063542143131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 1202182866481 + 111229587121 = 1096441^2 + 333511^2 .

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 328353113399 + ... + 328353113402.

Almost surely, 21313412453602 is an apocalyptic number.

1313412453602 is a deficient number, since it is larger than the sum of its proper divisors (656706226804).

1313412453602 is an equidigital number, since it uses as much as digits as its factorization.

1313412453602 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 656706226803.

The product of its (nonzero) digits is 51840, while the sum is 35.

Adding to 1313412453602 its reverse (2063542143131), we get a palindrome (3376954596733).

The spelling of 1313412453602 in words is "one trillion, three hundred thirteen billion, four hundred twelve million, four hundred fifty-three thousand, six hundred two".

Divisors: 1 2 656706226801 1313412453602