Base | Representation |
---|---|
bin | 10011000111001101011… |
… | …110111001010011100011 |
3 | 11122120010222020200200000 |
4 | 103013031132321103203 |
5 | 133004332042003403 |
6 | 2443212351031043 |
7 | 163614404436555 |
oct | 23071536712343 |
9 | 4576128220600 |
10 | 1313412453603 |
11 | 4670190a9098 |
12 | 19266b20b483 |
13 | 96b14a7b013 |
14 | 477d89db4d5 |
15 | 2427169a7a3 |
hex | 131cd7b94e3 |
1313412453603 has 24 divisors (see below), whose sum is σ = 2035258134000. Its totient is φ = 845414908128.
The previous prime is 1313412453589. The next prime is 1313412453623. The reversal of 1313412453603 is 3063542143131.
1313412453603 is a `hidden beast` number, since 1 + 3 + 1 + 3 + 4 + 1 + 2 + 45 + 3 + 603 = 666.
It is not a de Polignac number, because 1313412453603 - 25 = 1313412453571 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1313412453623) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 93182428 + ... + 93196521.
It is an arithmetic number, because the mean of its divisors is an integer number (84802422250).
Almost surely, 21313412453603 is an apocalyptic number.
1313412453603 is a deficient number, since it is larger than the sum of its proper divisors (721845680397).
1313412453603 is an equidigital number, since it uses as much as digits as its factorization.
1313412453603 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 186378993 (or 186378981 counting only the distinct ones).
The product of its (nonzero) digits is 77760, while the sum is 36.
Adding to 1313412453603 its reverse (3063542143131), we get a palindrome (4376954596734).
The spelling of 1313412453603 in words is "one trillion, three hundred thirteen billion, four hundred twelve million, four hundred fifty-three thousand, six hundred three".
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