Base | Representation |
---|---|
bin | 10011000111001101011… |
… | …110111001010011110111 |
3 | 11122120010222020200200202 |
4 | 103013031132321103313 |
5 | 133004332042003443 |
6 | 2443212351031115 |
7 | 163614404436614 |
oct | 23071536712367 |
9 | 4576128220622 |
10 | 1313412453623 |
11 | 4670190a9106 |
12 | 19266b20b49b |
13 | 96b14a7b02a |
14 | 477d89db50b |
15 | 2427169a7b8 |
hex | 131cd7b94f7 |
1313412453623 has 2 divisors, whose sum is σ = 1313412453624. Its totient is φ = 1313412453622.
The previous prime is 1313412453589. The next prime is 1313412453653. The reversal of 1313412453623 is 3263542143131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1313412453623 - 230 = 1312338711799 is a prime.
It is a super-2 number, since 2×13134124536232 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1313412453653) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656706226811 + 656706226812.
It is an arithmetic number, because the mean of its divisors is an integer number (656706226812).
Almost surely, 21313412453623 is an apocalyptic number.
1313412453623 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313412453623 is an equidigital number, since it uses as much as digits as its factorization.
1313412453623 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 155520, while the sum is 38.
Adding to 1313412453623 its reverse (3263542143131), we get a palindrome (4576954596754).
The spelling of 1313412453623 in words is "one trillion, three hundred thirteen billion, four hundred twelve million, four hundred fifty-three thousand, six hundred twenty-three".
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