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1313413345549 is a prime number
BaseRepresentation
bin10011000111001101100…
…010010011000100001101
311122120011000221000012001
4103013031202103010031
5133004332304024144
62443212422112301
7163614415143154
oct23071542230415
94576130830161
101313413345549
11467019658238
1219266b57b691
1396b15000cb6
14477d8b9059b
15242717c4bd4
hex131cd89310d

1313413345549 has 2 divisors, whose sum is σ = 1313413345550. Its totient is φ = 1313413345548.

The previous prime is 1313413345529. The next prime is 1313413345711. The reversal of 1313413345549 is 9455433143131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1298501272324 + 14912073225 = 1139518^2 + 122115^2 .

It is a cyclic number.

It is not a de Polignac number, because 1313413345549 - 27 = 1313413345421 is a prime.

It is a super-2 number, since 2×13134133455492 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1313413345499 and 1313413345508.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1313413345529) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656706672774 + 656706672775.

It is an arithmetic number, because the mean of its divisors is an integer number (656706672775).

Almost surely, 21313413345549 is an apocalyptic number.

It is an amenable number.

1313413345549 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313413345549 is an equidigital number, since it uses as much as digits as its factorization.

1313413345549 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1166400, while the sum is 46.

The spelling of 1313413345549 in words is "one trillion, three hundred thirteen billion, four hundred thirteen million, three hundred forty-five thousand, five hundred forty-nine".