Base | Representation |
---|---|
bin | 10011000111001101100… |
… | …101111110110001011100 |
3 | 11122120011002202001112122 |
4 | 103013031211332301130 |
5 | 133004333030423004 |
6 | 2443212454522112 |
7 | 163614426303665 |
oct | 23071545766134 |
9 | 4576132661478 |
10 | 1313414311004 |
11 | 46701a157634 |
12 | 19266b966338 |
13 | 96b1527b583 |
14 | 477d8d6236c |
15 | 24271915cbe |
hex | 131cd97ec5c |
1313414311004 has 6 divisors (see below), whose sum is σ = 2298475044264. Its totient is φ = 656707155500.
The previous prime is 1313414311003. The next prime is 1313414311151. The reversal of 1313414311004 is 4001134143131.
It is a super-3 number, since 3×13134143110043 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1313414311003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 164176788872 + ... + 164176788879.
It is an arithmetic number, because the mean of its divisors is an integer number (383079174044).
Almost surely, 21313414311004 is an apocalyptic number.
It is an amenable number.
1313414311004 is a deficient number, since it is larger than the sum of its proper divisors (985060733260).
1313414311004 is a wasteful number, since it uses less digits than its factorization.
1313414311004 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 328353577755 (or 328353577753 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 26.
Adding to 1313414311004 its reverse (4001134143131), we get a palindrome (5314548454135).
The spelling of 1313414311004 in words is "one trillion, three hundred thirteen billion, four hundred fourteen million, three hundred eleven thousand, four".
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