1313414311003 has 2 divisors, whose sum is σ = 1313414311004. Its totient is φ = 1313414311002.

The previous prime is 1313414310959. The next prime is 1313414311151. The reversal of 1313414311003 is 3001134143131.

It is a weak prime.

It is an emirp because it is prime and its reverse (3001134143131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1313414311003 is a prime.

It is not a weakly prime, because it can be changed into another prime (1313414311603) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656707155501 + 656707155502.

It is an arithmetic number, because the mean of its divisors is an integer number (656707155502).

Almost surely, 2^{1313414311003} is an apocalyptic number.

1313414311003 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313414311003 is an equidigital number, since it uses as much as digits as its factorization.

1313414311003 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 1313414311003 its reverse (3001134143131), we get a palindrome (4314548454134).

The spelling of 1313414311003 in words is "one trillion, three hundred thirteen billion, four hundred fourteen million, three hundred eleven thousand, three".