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1313414311603 is a prime number
BaseRepresentation
bin10011000111001101100…
…101111110111010110011
311122120011002202002100211
4103013031211332322303
5133004333030432403
62443212454524551
7163614426305512
oct23071545767263
94576132662324
101313414311603
1146701a158029
1219266b966757
1396b1527b924
14477d8d62679
152427191606d
hex131cd97eeb3

1313414311603 has 2 divisors, whose sum is σ = 1313414311604. Its totient is φ = 1313414311602.

The previous prime is 1313414311567. The next prime is 1313414311607. The reversal of 1313414311603 is 3061134143131.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1313414311603 is a prime.

It is not a weakly prime, because it can be changed into another prime (1313414311607) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656707155801 + 656707155802.

It is an arithmetic number, because the mean of its divisors is an integer number (656707155802).

Almost surely, 21313414311603 is an apocalyptic number.

1313414311603 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313414311603 is an equidigital number, since it uses as much as digits as its factorization.

1313414311603 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7776, while the sum is 31.

Adding to 1313414311603 its reverse (3061134143131), we get a palindrome (4374548454734).

The spelling of 1313414311603 in words is "one trillion, three hundred thirteen billion, four hundred fourteen million, three hundred eleven thousand, six hundred three".