Base | Representation |
---|---|
bin | 1011111100100000100100… |
… | …1111011110110010111100 |
3 | 1201111121120112200221201110 |
4 | 2333020021033132302330 |
5 | 3210142232222410122 |
6 | 43533430243042020 |
7 | 2523624565561356 |
oct | 277101117366274 |
9 | 51447515627643 |
10 | 13134165044412 |
11 | 4204193840395 |
12 | 15815a5370310 |
13 | 74371471a169 |
14 | 3359a87280d6 |
15 | 17b9b2ec290c |
hex | bf2093decbc |
13134165044412 has 12 divisors (see below), whose sum is σ = 30646385103656. Its totient is φ = 4378055014800.
The previous prime is 13134165044411. The next prime is 13134165044471. The reversal of 13134165044412 is 21444056143131.
It is a tau number, because it is divible by the number of its divisors (12).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13134165044411) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 547256876839 + ... + 547256876862.
Almost surely, 213134165044412 is an apocalyptic number.
13134165044412 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
13134165044412 is an abundant number, since it is smaller than the sum of its proper divisors (17512220059244).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13134165044412 is a wasteful number, since it uses less digits than its factorization.
13134165044412 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1094513753708 (or 1094513753706 counting only the distinct ones).
The product of its (nonzero) digits is 138240, while the sum is 39.
The spelling of 13134165044412 in words is "thirteen trillion, one hundred thirty-four billion, one hundred sixty-five million, forty-four thousand, four hundred twelve".
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