Base | Representation |
---|---|
bin | 11101110111010001111111… |
… | …001110011110101111011100 |
3 | 122020001012021010212021100011 |
4 | 131313101333032132233130 |
5 | 114203402344002222134 |
6 | 1143201442311413004 |
7 | 36444110003034463 |
oct | 3567217716365734 |
9 | 566035233767304 |
10 | 131342234414044 |
11 | 38938a24272835 |
12 | 12893008684164 |
13 | 583969a622664 |
14 | 2460dd898d9da |
15 | 102b7a621e264 |
hex | 77747f39ebdc |
131342234414044 has 48 divisors (see below), whose sum is σ = 231395525928000. Its totient is φ = 65230742693376.
The previous prime is 131342234414023. The next prime is 131342234414047. The reversal of 131342234414044 is 440414432243131.
It is a junction number, because it is equal to n+sod(n) for n = 131342234413988 and 131342234414006.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131342234414047) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3476206777 + ... + 3476244559.
It is an arithmetic number, because the mean of its divisors is an integer number (4820740123500).
Almost surely, 2131342234414044 is an apocalyptic number.
It is an amenable number.
131342234414044 is a deficient number, since it is larger than the sum of its proper divisors (100053291513956).
131342234414044 is a wasteful number, since it uses less digits than its factorization.
131342234414044 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 47662 (or 47660 counting only the distinct ones).
The product of its (nonzero) digits is 442368, while the sum is 40.
Adding to 131342234414044 its reverse (440414432243131), we get a palindrome (571756666657175).
The spelling of 131342234414044 in words is "one hundred thirty-one trillion, three hundred forty-two billion, two hundred thirty-four million, four hundred fourteen thousand, forty-four".
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