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13134232334381 is a prime number
BaseRepresentation
bin1011111100100000110101…
…0000001011000000101101
31201111121202020022122012112
42333020031100023000231
53210142401434200011
643533441045213405
72523626343540134
oct277101520130055
951447666278175
1013134232334381
114204218820334
121581603a01265
1374372564a302
143359b364291b
1517b9b8d6558b
hexbf20d40b02d

13134232334381 has 2 divisors, whose sum is σ = 13134232334382. Its totient is φ = 13134232334380.

The previous prime is 13134232334369. The next prime is 13134232334429. The reversal of 13134232334381 is 18343323243131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10774583041156 + 2359649293225 = 3282466^2 + 1536115^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13134232334381 is a prime.

It is a super-2 number, since 2×131342323343812 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13134232334351) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6567116167190 + 6567116167191.

It is an arithmetic number, because the mean of its divisors is an integer number (6567116167191).

Almost surely, 213134232334381 is an apocalyptic number.

It is an amenable number.

13134232334381 is a deficient number, since it is larger than the sum of its proper divisors (1).

13134232334381 is an equidigital number, since it uses as much as digits as its factorization.

13134232334381 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 373248, while the sum is 41.

The spelling of 13134232334381 in words is "thirteen trillion, one hundred thirty-four billion, two hundred thirty-two million, three hundred thirty-four thousand, three hundred eighty-one".