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131342430240977 is a prime number
BaseRepresentation
bin11101110111010010001010…
…111001100000000011010001
3122020001012202210100022101112
4131313102022321200003101
5114203403244120202402
61143201513544543105
736444114601401464
oct3567221271400321
9566035683308345
10131342430240977
113893901486547a
1212893062181a95
1358396cc078397
1424610169a72db
15102b7b8501e52
hex77748ae600d1

131342430240977 has 2 divisors, whose sum is σ = 131342430240978. Its totient is φ = 131342430240976.

The previous prime is 131342430240953. The next prime is 131342430240979. The reversal of 131342430240977 is 779042034243131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 83089623853201 + 48252806387776 = 9115351^2 + 6946424^2 .

It is a cyclic number.

It is not a de Polignac number, because 131342430240977 - 218 = 131342429978833 is a prime.

Together with 131342430240979, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (131342430240979) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65671215120488 + 65671215120489.

It is an arithmetic number, because the mean of its divisors is an integer number (65671215120489).

Almost surely, 2131342430240977 is an apocalyptic number.

It is an amenable number.

131342430240977 is a deficient number, since it is larger than the sum of its proper divisors (1).

131342430240977 is an equidigital number, since it uses as much as digits as its factorization.

131342430240977 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3048192, while the sum is 50.

The spelling of 131342430240977 in words is "one hundred thirty-one trillion, three hundred forty-two billion, four hundred thirty million, two hundred forty thousand, nine hundred seventy-seven".