Base | Representation |
---|---|
bin | 1011111100100001000110… |
… | …0010001100101001011111 |
3 | 1201111121221020111012011001 |
4 | 2333020101202030221133 |
5 | 3210143023331343133 |
6 | 43533452133011131 |
7 | 2523631205243155 |
oct | 277102142145137 |
9 | 51447836435131 |
10 | 13134304168543 |
11 | 4204255324408 |
12 | 1581623a83aa7 |
13 | 7437374ab92c |
14 | 3359bcdc13d5 |
15 | 17b9c030487d |
hex | bf21188ca5f |
13134304168543 has 2 divisors, whose sum is σ = 13134304168544. Its totient is φ = 13134304168542.
The previous prime is 13134304168523. The next prime is 13134304168567. The reversal of 13134304168543 is 34586140343131.
13134304168543 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13134304168543 - 25 = 13134304168511 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13134304168493 and 13134304168502.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13134304168523) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6567152084271 + 6567152084272.
It is an arithmetic number, because the mean of its divisors is an integer number (6567152084272).
Almost surely, 213134304168543 is an apocalyptic number.
13134304168543 is a deficient number, since it is larger than the sum of its proper divisors (1).
13134304168543 is an equidigital number, since it uses as much as digits as its factorization.
13134304168543 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1244160, while the sum is 46.
The spelling of 13134304168543 in words is "thirteen trillion, one hundred thirty-four billion, three hundred four million, one hundred sixty-eight thousand, five hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •