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131343204120442 = 2131501309939391
BaseRepresentation
bin11101110111010010111001…
…000001100111011101111010
3122020001021202201112110102221
4131313102321001213131322
5114203411340223323232
61143202122431514254
736444143016305026
oct3567227101473572
9566037681473387
10131343204120442
1138939381685586
121289323938898a
1358397c34b4022
14246108b693386
15102b811419897
hex7774b906777a

131343204120442 has 8 divisors (see below), whose sum is σ = 198518735999232. Its totient is φ = 65170292120700.

The previous prime is 131343204120433. The next prime is 131343204120481. The reversal of 131343204120442 is 244021402343131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 131343204120398 and 131343204120407.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 250654969434 + ... + 250654969957.

It is an arithmetic number, because the mean of its divisors is an integer number (24814841999904).

Almost surely, 2131343204120442 is an apocalyptic number.

131343204120442 is a deficient number, since it is larger than the sum of its proper divisors (67175531878790).

131343204120442 is a wasteful number, since it uses less digits than its factorization.

131343204120442 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 501309939524.

The product of its (nonzero) digits is 55296, while the sum is 34.

Adding to 131343204120442 its reverse (244021402343131), we get a palindrome (375364606463573).

The spelling of 131343204120442 in words is "one hundred thirty-one trillion, three hundred forty-three billion, two hundred four million, one hundred twenty thousand, four hundred forty-two".

Divisors: 1 2 131 262 501309939391 1002619878782 65671602060221 131343204120442