Base | Representation |
---|---|
bin | 11101110111010010111010… |
… | …101100000010111111011000 |
3 | 122020001021211200000221001012 |
4 | 131313102322230002333120 |
5 | 114203411414344123230 |
6 | 1143202125305513052 |
7 | 36444143505406106 |
oct | 3567227254027730 |
9 | 566037750027035 |
10 | 131343232020440 |
11 | 38939396401230 |
12 | 128932467a2788 |
13 | 58397c92021bb |
14 | 2461091276c76 |
15 | 102b813acb395 |
hex | 7774bab02fd8 |
131343232020440 has 256 divisors, whose sum is σ = 328749472972800. Its totient is φ = 46824041779200.
The previous prime is 131343232020349. The next prime is 131343232020601. The reversal of 131343232020440 is 44020232343131.
It is a junction number, because it is equal to n+sod(n) for n = 131343232020397 and 131343232020406.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 19665101021 + ... + 19665107699.
It is an arithmetic number, because the mean of its divisors is an integer number (1284177628800).
Almost surely, 2131343232020440 is an apocalyptic number.
131343232020440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 131343232020440, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (164374736486400).
131343232020440 is an abundant number, since it is smaller than the sum of its proper divisors (197406240952360).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131343232020440 is a wasteful number, since it uses less digits than its factorization.
131343232020440 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9058 (or 9054 counting only the distinct ones).
The product of its (nonzero) digits is 41472, while the sum is 32.
Adding to 131343232020440 its reverse (44020232343131), we get a palindrome (175363464363571).
The spelling of 131343232020440 in words is "one hundred thirty-one trillion, three hundred forty-three billion, two hundred thirty-two million, twenty thousand, four hundred forty".
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