Base | Representation |
---|---|
bin | 11101110111010011000111… |
… | …010100110001101010111111 |
3 | 122020001022101102221211020212 |
4 | 131313103013110301222333 |
5 | 114203412333132231444 |
6 | 1143202202321503035 |
7 | 36444151661406224 |
oct | 3567230724615277 |
9 | 566038342854225 |
10 | 131343444023999 |
11 | 38939495042689 |
12 | 128932a57a1a7b |
13 | 58398310cccac |
14 | 24610b14a194b |
15 | 102b82750719e |
hex | 7774c7531abf |
131343444023999 has 2 divisors, whose sum is σ = 131343444024000. Its totient is φ = 131343444023998.
The previous prime is 131343444023941. The next prime is 131343444024031. The reversal of 131343444023999 is 999320444343131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131343444023999 is a prime.
It is a super-2 number, since 2×1313434440239992 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131343444023929) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65671722011999 + 65671722012000.
It is an arithmetic number, because the mean of its divisors is an integer number (65671722012000).
Almost surely, 2131343444023999 is an apocalyptic number.
131343444023999 is a deficient number, since it is larger than the sum of its proper divisors (1).
131343444023999 is an equidigital number, since it uses as much as digits as its factorization.
131343444023999 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 30233088, while the sum is 59.
The spelling of 131343444023999 in words is "one hundred thirty-one trillion, three hundred forty-three billion, four hundred forty-four million, twenty-three thousand, nine hundred ninety-nine".
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