Base | Representation |
---|---|
bin | 1011111100100001001111… |
… | …1011101011010111100111 |
3 | 1201111122001001012021122011 |
4 | 2333020103323223113213 |
5 | 3210143114131334112 |
6 | 43533500131215051 |
7 | 2523632204234104 |
oct | 277102373532747 |
9 | 51448031167564 |
10 | 13134344402407 |
11 | 4204276004738 |
12 | 1581635447487 |
13 | 743742927a57 |
14 | 3359c4495aab |
15 | 17b9c3b00aa7 |
hex | bf213eeb5e7 |
13134344402407 has 2 divisors, whose sum is σ = 13134344402408. Its totient is φ = 13134344402406.
The previous prime is 13134344402363. The next prime is 13134344402461. The reversal of 13134344402407 is 70420444343131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13134344402407 - 231 = 13132196918759 is a prime.
It is a super-2 number, since 2×131343444024072 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13134344402407.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13134344402477) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6567172201203 + 6567172201204.
It is an arithmetic number, because the mean of its divisors is an integer number (6567172201204).
Almost surely, 213134344402407 is an apocalyptic number.
13134344402407 is a deficient number, since it is larger than the sum of its proper divisors (1).
13134344402407 is an equidigital number, since it uses as much as digits as its factorization.
13134344402407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 387072, while the sum is 40.
Adding to 13134344402407 its reverse (70420444343131), we get a palindrome (83554788745538).
The spelling of 13134344402407 in words is "thirteen trillion, one hundred thirty-four billion, three hundred forty-four million, four hundred two thousand, four hundred seven".
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