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131343983 is a prime number
BaseRepresentation
bin1111101010000…
…10011001101111
3100011010222001222
413311002121233
5232111001413
621011053555
73153256031
oct765023157
9304128058
10131343983
116815a751
1237ba12bb
1321299444
141362dc51
15b7e6b08
hex7d4266f

131343983 has 2 divisors, whose sum is σ = 131343984. Its totient is φ = 131343982.

The previous prime is 131343967. The next prime is 131344013. The reversal of 131343983 is 389343131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131343983 - 24 = 131343967 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131343943) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65671991 + 65671992.

It is an arithmetic number, because the mean of its divisors is an integer number (65671992).

Almost surely, 2131343983 is an apocalyptic number.

131343983 is a deficient number, since it is larger than the sum of its proper divisors (1).

131343983 is an equidigital number, since it uses as much as digits as its factorization.

131343983 is an evil number, because the sum of its binary digits is even.

The product of its digits is 23328, while the sum is 35.

The square root of 131343983 is about 11460.5402577714. The cubic root of 131343983 is about 508.3194497567.

The spelling of 131343983 in words is "one hundred thirty-one million, three hundred forty-three thousand, nine hundred eighty-three".