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131344414301 is a prime number
BaseRepresentation
bin111101001010010111…
…1001011011001011101
3110120000121200120100002
41322110233023121131
54122443132224201
6140201102344045
712326560046402
oct1722457133135
9416017616302
10131344414301
1150780552531
1221556b8b025
13c502590659
1464ddc6c2a9
15363adc876b
hex1e94bcb65d

131344414301 has 2 divisors, whose sum is σ = 131344414302. Its totient is φ = 131344414300.

The previous prime is 131344414249. The next prime is 131344414433. The reversal of 131344414301 is 103414443131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 71540200900 + 59804213401 = 267470^2 + 244549^2 .

It is a cyclic number.

It is not a de Polignac number, because 131344414301 - 218 = 131344152157 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131344414601) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65672207150 + 65672207151.

It is an arithmetic number, because the mean of its divisors is an integer number (65672207151).

Almost surely, 2131344414301 is an apocalyptic number.

It is an amenable number.

131344414301 is a deficient number, since it is larger than the sum of its proper divisors (1).

131344414301 is an equidigital number, since it uses as much as digits as its factorization.

131344414301 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 131344414301 its reverse (103414443131), we get a palindrome (234758857432).

The spelling of 131344414301 in words is "one hundred thirty-one billion, three hundred forty-four million, four hundred fourteen thousand, three hundred one".