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13134443100 = 22352172197769
BaseRepresentation
bin11000011101101111…
…11011001001011100
31020220100202211201120
430032313323021130
5203344404134400
610011152410540
7643324632012
oct141667731134
936810684646
1013134443100
115630061559
122666846a50
1313141b492c
148c85648b2
1551d15bca0
hex30edfb25c

13134443100 has 216 divisors, whose sum is σ = 40626930960. Its totient is φ = 3275489280.

The previous prime is 13134443071. The next prime is 13134443137. The reversal of 13134443100 is 134443131.

It is a super-2 number, since 2×131344431002 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 17079516 + ... + 17080284.

Almost surely, 213134443100 is an apocalyptic number.

13134443100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13134443100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20313465480).

13134443100 is an abundant number, since it is smaller than the sum of its proper divisors (27492487860).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13134443100 is a wasteful number, since it uses less digits than its factorization.

13134443100 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1017 (or 993 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 13134443100 its reverse (134443131), we get a palindrome (13268886231).

The spelling of 13134443100 in words is "thirteen billion, one hundred thirty-four million, four hundred forty-three thousand, one hundred".