Base | Representation |
---|---|
bin | 1011111100100001101010… |
… | …1111110110000110010101 |
3 | 1201111122100000100021220002 |
4 | 2333020122233312012111 |
5 | 3210143332414204031 |
6 | 43533515334021045 |
7 | 2523635063136143 |
oct | 277103257660625 |
9 | 51448300307802 |
10 | 13134458741141 |
11 | 42043245aa061 |
12 | 15816677a7785 |
13 | 74376051bbca |
14 | 3359d573a593 |
15 | 17b9cdb88ccb |
hex | bf21abf6195 |
13134458741141 has 4 divisors (see below), whose sum is σ = 13134577888800. Its totient is φ = 13134339593484.
The previous prime is 13134458741119. The next prime is 13134458741147. The reversal of 13134458741141 is 14114785443131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13134458741141 - 238 = 12859580834197 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13134458741147) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59408321 + ... + 59628998.
It is an arithmetic number, because the mean of its divisors is an integer number (3283644472200).
Almost surely, 213134458741141 is an apocalyptic number.
It is an amenable number.
13134458741141 is a deficient number, since it is larger than the sum of its proper divisors (119147659).
13134458741141 is a wasteful number, since it uses less digits than its factorization.
13134458741141 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 119147658.
The product of its digits is 645120, while the sum is 47.
The spelling of 13134458741141 in words is "thirteen trillion, one hundred thirty-four billion, four hundred fifty-eight million, seven hundred forty-one thousand, one hundred forty-one".
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