Base | Representation |
---|---|
bin | 1011111100100001101010… |
… | …1111110110000110010110 |
3 | 1201111122100000100021220010 |
4 | 2333020122233312012112 |
5 | 3210143332414204032 |
6 | 43533515334021050 |
7 | 2523635063136144 |
oct | 277103257660626 |
9 | 51448300307803 |
10 | 13134458741142 |
11 | 42043245aa062 |
12 | 15816677a7786 |
13 | 74376051bbcb |
14 | 3359d573a594 |
15 | 17b9cdb88ccc |
hex | bf21abf6196 |
13134458741142 has 16 divisors (see below), whose sum is σ = 26269082818992. Its totient is φ = 4378125357600.
The previous prime is 13134458741119. The next prime is 13134458741147. The reversal of 13134458741142 is 24114785443131.
It is a super-2 number, since 2×131344587411422 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13134458741091 and 13134458741100.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13134458741147) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5844109 + ... + 7773192.
It is an arithmetic number, because the mean of its divisors is an integer number (1641817676187).
Almost surely, 213134458741142 is an apocalyptic number.
13134458741142 is an abundant number, since it is smaller than the sum of its proper divisors (13134624077850).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13134458741142 is a wasteful number, since it uses less digits than its factorization.
13134458741142 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13778063.
The product of its digits is 1290240, while the sum is 48.
The spelling of 13134458741142 in words is "thirteen trillion, one hundred thirty-four billion, four hundred fifty-eight million, seven hundred forty-one thousand, one hundred forty-two".
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