Base | Representation |
---|---|
bin | 11101110111010100111101… |
… | …001010011001011110001011 |
3 | 122020001111111020000100221221 |
4 | 131313110331022121132023 |
5 | 114203430410234434143 |
6 | 1143203130423342511 |
7 | 36444251655510163 |
oct | 3567247512313613 |
9 | 566044436010857 |
10 | 131345421014923 |
11 | 3893a309aa4185 |
12 | 128937578b1a37 |
13 | 5839a8787c3cb |
14 | 246121bc8b5a3 |
15 | 102b8e0d722ed |
hex | 77753d29978b |
131345421014923 has 2 divisors, whose sum is σ = 131345421014924. Its totient is φ = 131345421014922.
The previous prime is 131345421014893. The next prime is 131345421015001. The reversal of 131345421014923 is 329410124543131.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131345421014923 - 217 = 131345420883851 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 131345421014923.
It is not a weakly prime, because it can be changed into another prime (131345421018923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65672710507461 + 65672710507462.
It is an arithmetic number, because the mean of its divisors is an integer number (65672710507462).
Almost surely, 2131345421014923 is an apocalyptic number.
131345421014923 is a deficient number, since it is larger than the sum of its proper divisors (1).
131345421014923 is an equidigital number, since it uses as much as digits as its factorization.
131345421014923 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 311040, while the sum is 43.
The spelling of 131345421014923 in words is "one hundred thirty-one trillion, three hundred forty-five billion, four hundred twenty-one million, fourteen thousand, nine hundred twenty-three".
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