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131345421014923 is a prime number
BaseRepresentation
bin11101110111010100111101…
…001010011001011110001011
3122020001111111020000100221221
4131313110331022121132023
5114203430410234434143
61143203130423342511
736444251655510163
oct3567247512313613
9566044436010857
10131345421014923
113893a309aa4185
12128937578b1a37
135839a8787c3cb
14246121bc8b5a3
15102b8e0d722ed
hex77753d29978b

131345421014923 has 2 divisors, whose sum is σ = 131345421014924. Its totient is φ = 131345421014922.

The previous prime is 131345421014893. The next prime is 131345421015001. The reversal of 131345421014923 is 329410124543131.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131345421014923 - 217 = 131345420883851 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 131345421014923.

It is not a weakly prime, because it can be changed into another prime (131345421018923) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65672710507461 + 65672710507462.

It is an arithmetic number, because the mean of its divisors is an integer number (65672710507462).

Almost surely, 2131345421014923 is an apocalyptic number.

131345421014923 is a deficient number, since it is larger than the sum of its proper divisors (1).

131345421014923 is an equidigital number, since it uses as much as digits as its factorization.

131345421014923 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 311040, while the sum is 43.

The spelling of 131345421014923 in words is "one hundred thirty-one trillion, three hundred forty-five billion, four hundred twenty-one million, fourteen thousand, nine hundred twenty-three".