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13134750229543 is a prime number
BaseRepresentation
bin1011111100100010110000…
…0111110010010000100111
31201111200002022211102210211
42333020230013302100213
53210144432024321133
643534004305400251
72523645232555435
oct277105407622047
951450068742724
1013134750229543
11420446409a668
121581729339087
137437a8a29757
14335a22335d55
1517b9e9565bcd
hexbf22c1f2427

13134750229543 has 2 divisors, whose sum is σ = 13134750229544. Its totient is φ = 13134750229542.

The previous prime is 13134750229511. The next prime is 13134750229547. The reversal of 13134750229543 is 34592205743131.

13134750229543 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (34592205743131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13134750229543 - 25 = 13134750229511 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13134750229547) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6567375114771 + 6567375114772.

It is an arithmetic number, because the mean of its divisors is an integer number (6567375114772).

Almost surely, 213134750229543 is an apocalyptic number.

13134750229543 is a deficient number, since it is larger than the sum of its proper divisors (1).

13134750229543 is an equidigital number, since it uses as much as digits as its factorization.

13134750229543 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2721600, while the sum is 49.

The spelling of 13134750229543 in words is "thirteen trillion, one hundred thirty-four billion, seven hundred fifty million, two hundred twenty-nine thousand, five hundred forty-three".