Base | Representation |
---|---|
bin | 1011111100100011101101… |
… | …0110000100110100010001 |
3 | 1201111200202010102022121002 |
4 | 2333020323112010310101 |
5 | 3210200442420240214 |
6 | 43534045511511345 |
7 | 2523654453506333 |
oct | 277107326046421 |
9 | 51450663368532 |
10 | 13135005633809 |
11 | 4204585284674 |
12 | 158179a988555 |
13 | 743819911c37 |
14 | 335a4821b453 |
15 | 17ba11bb61de |
hex | bf23b584d11 |
13135005633809 has 2 divisors, whose sum is σ = 13135005633810. Its totient is φ = 13135005633808.
The previous prime is 13135005633803. The next prime is 13135005633877. The reversal of 13135005633809 is 90833650053131.
13135005633809 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13094736382225 + 40269251584 = 3618665^2 + 200672^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13135005633809 is a prime.
It is not a weakly prime, because it can be changed into another prime (13135005633803) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6567502816904 + 6567502816905.
It is an arithmetic number, because the mean of its divisors is an integer number (6567502816905).
Almost surely, 213135005633809 is an apocalyptic number.
It is an amenable number.
13135005633809 is a deficient number, since it is larger than the sum of its proper divisors (1).
13135005633809 is an equidigital number, since it uses as much as digits as its factorization.
13135005633809 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 874800, while the sum is 47.
The spelling of 13135005633809 in words is "thirteen trillion, one hundred thirty-five billion, five million, six hundred thirty-three thousand, eight hundred nine".
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