13135022411001 has 4 divisors (see below), whose sum is σ = 17513363214672. Its totient is φ = 8756681607332.

The previous prime is 13135022410901. The next prime is 13135022411113. The reversal of 13135022411001 is 10011422053131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13135022411001 - 2¹¹ = 13135022408953 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13135022416001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2189170401831 + ... + 2189170401836.

It is an arithmetic number, because the mean of its divisors is an integer number (4378340803668).

Almost surely, 2^{13135022411001} is an apocalyptic number.

It is an amenable number.

13135022411001 is a deficient number, since it is larger than the sum of its proper divisors (4378340803671).

13135022411001 is an equidigital number, since it uses as much as digits as its factorization.

13135022411001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4378340803670.

The product of its (nonzero) digits is 720, while the sum is 24.

Adding to 13135022411001 its reverse (10011422053131), we get a palindrome (23146444464132).

The spelling of 13135022411001 in words is "thirteen trillion, one hundred thirty-five billion, twenty-two million, four hundred eleven thousand, one".