13135022411113 has 2 divisors, whose sum is σ = 13135022411114. Its totient is φ = 13135022411112.

The previous prime is 13135022410901. The next prime is 13135022411131. The reversal of 13135022411113 is 31111422053131.

It is a happy number.

Together with next prime (13135022411131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7870420652329 + 5264601758784 = 2805427^2 + 2294472^2 .

It is a cyclic number.

It is not a de Polignac number, because 13135022411113 - 2¹³ = 13135022402921 is a prime.

It is not a weakly prime, because it can be changed into another prime (13135022411153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6567511205556 + 6567511205557.

It is an arithmetic number, because the mean of its divisors is an integer number (6567511205557).

Almost surely, 2^{13135022411113} is an apocalyptic number.

It is an amenable number.

13135022411113 is a deficient number, since it is larger than the sum of its proper divisors (1).

13135022411113 is an equidigital number, since it uses as much as digits as its factorization.

13135022411113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2160, while the sum is 28.

Adding to 13135022411113 its reverse (31111422053131), we get a palindrome (44246444464244).

The spelling of 13135022411113 in words is "thirteen trillion, one hundred thirty-five billion, twenty-two million, four hundred eleven thousand, one hundred thirteen".