Base | Representation |
---|---|
bin | 1011111100100011110001… |
… | …0110000100110010010101 |
3 | 1201111200210021222200102212 |
4 | 2333020330112010302111 |
5 | 3210201011214122101 |
6 | 43534051311243205 |
7 | 2523655046223206 |
oct | 277107426046225 |
9 | 51450707880385 |
10 | 13135022410901 |
11 | 42045937a3536 |
12 | 15817a4519505 |
13 | 743820237401 |
14 | 335a4a5475ad |
15 | 17ba133cc1bb |
hex | bf23c584c95 |
13135022410901 has 2 divisors, whose sum is σ = 13135022410902. Its totient is φ = 13135022410900.
The previous prime is 13135022410879. The next prime is 13135022411113. The reversal of 13135022410901 is 10901422053131.
13135022410901 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12361060588900 + 773961822001 = 3515830^2 + 879751^2 .
It is a cyclic number.
It is not a de Polignac number, because 13135022410901 - 26 = 13135022410837 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13135022410201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6567511205450 + 6567511205451.
It is an arithmetic number, because the mean of its divisors is an integer number (6567511205451).
Almost surely, 213135022410901 is an apocalyptic number.
It is an amenable number.
13135022410901 is a deficient number, since it is larger than the sum of its proper divisors (1).
13135022410901 is an equidigital number, since it uses as much as digits as its factorization.
13135022410901 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6480, while the sum is 32.
The spelling of 13135022410901 in words is "thirteen trillion, one hundred thirty-five billion, twenty-two million, four hundred ten thousand, nine hundred one".
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