Base | Representation |
---|---|
bin | 1011111100100100000101… |
… | …0001101101010000011111 |
3 | 1201111201000001200100221011 |
4 | 2333021001101231100133 |
5 | 3210201143404331111 |
6 | 43534103424520051 |
7 | 2523660102424042 |
oct | 277110121552037 |
9 | 51451001610834 |
10 | 13135105152031 |
11 | 4204626477135 |
12 | 1581808180027 |
13 | 743834417365 |
14 | 335a57524c59 |
15 | 17ba1a7c3021 |
hex | bf24146d41f |
13135105152031 has 2 divisors, whose sum is σ = 13135105152032. Its totient is φ = 13135105152030.
The previous prime is 13135105152019. The next prime is 13135105152041. The reversal of 13135105152031 is 13025150153131.
13135105152031 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13135105152031 - 211 = 13135105149983 is a prime.
It is a super-2 number, since 2×131351051520312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13135105151984 and 13135105152002.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13135105152041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6567552576015 + 6567552576016.
It is an arithmetic number, because the mean of its divisors is an integer number (6567552576016).
Almost surely, 213135105152031 is an apocalyptic number.
13135105152031 is a deficient number, since it is larger than the sum of its proper divisors (1).
13135105152031 is an equidigital number, since it uses as much as digits as its factorization.
13135105152031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6750, while the sum is 31.
The spelling of 13135105152031 in words is "thirteen trillion, one hundred thirty-five billion, one hundred five million, one hundred fifty-two thousand, thirty-one".
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