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131353200000 = 2732551131107
BaseRepresentation
bin111101001010101000…
…0101100010110000000
3110120001020012221001100
41322111100230112000
54123002404400000
6140202014534400
712330024530601
oct1722520542600
9416036187040
10131353200000
1150785503340
1221559b07400
13c5043485a9
1465010b7da8
15363ba61a00
hex1e9542c580

131353200000 has 1152 divisors, whose sum is σ = 536995630080. Its totient is φ = 30528000000.

The previous prime is 131353199963. The next prime is 131353200001. The reversal of 131353200000 is 2353131.

131353200000 is a `hidden beast` number, since 131 + 3 + 532 + 0 + 0 + 0 + 0 + 0 = 666.

It is a tau number, because it is divible by the number of its divisors (1152).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131353200001) by changing a digit.

It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 1227599947 + ... + 1227600053.

It is an arithmetic number, because the mean of its divisors is an integer number (466142040).

Almost surely, 2131353200000 is an apocalyptic number.

131353200000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131353200000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (268497815040).

131353200000 is an abundant number, since it is smaller than the sum of its proper divisors (405642430080).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131353200000 is a wasteful number, since it uses less digits than its factorization.

131353200000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 194 (or 159 counting only the distinct ones).

The product of its (nonzero) digits is 270, while the sum is 18.

Adding to 131353200000 its reverse (2353131), we get a palindrome (131355553131).

The spelling of 131353200000 in words is "one hundred thirty-one billion, three hundred fifty-three million, two hundred thousand".