Base | Representation |
---|---|
bin | 1011111100100100111011… |
… | …1100010110000101101111 |
3 | 1201111201121001010001110220 |
4 | 2333021032330112011233 |
5 | 3210202131103330020 |
6 | 43534142255102423 |
7 | 2523665555324055 |
oct | 277111674260557 |
9 | 51451531101426 |
10 | 13135334433135 |
11 | 4204733939452 |
12 | 1581870b11a13 |
13 | 74386ca84355 |
14 | 335a79b6a1d5 |
15 | 17ba309b3240 |
hex | bf24ef1616f |
13135334433135 has 32 divisors (see below), whose sum is σ = 22156072722432. Its totient is φ = 6635282173440.
The previous prime is 13135334433113. The next prime is 13135334433157. The reversal of 13135334433135 is 53133443353131.
It is an interprime number because it is at equal distance from previous prime (13135334433113) and next prime (13135334433157).
It is not a de Polignac number, because 13135334433135 - 217 = 13135334302063 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 300489114 + ... + 300532823.
It is an arithmetic number, because the mean of its divisors is an integer number (692377272576).
Almost surely, 213135334433135 is an apocalyptic number.
13135334433135 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13135334433135 is a deficient number, since it is larger than the sum of its proper divisors (9020738289297).
13135334433135 is a wasteful number, since it uses less digits than its factorization.
13135334433135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 601022023.
The product of its digits is 874800, while the sum is 42.
Adding to 13135334433135 its reverse (53133443353131), we get a palindrome (66268777786266).
The spelling of 13135334433135 in words is "thirteen trillion, one hundred thirty-five billion, three hundred thirty-four million, four hundred thirty-three thousand, one hundred thirty-five".
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