Base | Representation |
---|---|
bin | 10011000111010110011… |
… | …110111010011111111111 |
3 | 11122120112111101021111112 |
4 | 103013112132322133333 |
5 | 133010134221002224 |
6 | 2443235343312235 |
7 | 163621220062406 |
oct | 23072636723777 |
9 | 4576474337445 |
10 | 1313563453439 |
11 | 467096363546 |
12 | 1926b18ab67b |
13 | 96b3a13a033 |
14 | 47810aa663d |
15 | 2427ea7630e |
hex | 131d67ba7ff |
1313563453439 has 2 divisors, whose sum is σ = 1313563453440. Its totient is φ = 1313563453438.
The previous prime is 1313563453421. The next prime is 1313563453453. The reversal of 1313563453439 is 9343543653131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1313563453439 - 232 = 1309268486143 is a prime.
It is a super-3 number, since 3×13135634534393 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1313563453639) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656781726719 + 656781726720.
It is an arithmetic number, because the mean of its divisors is an integer number (656781726720).
Almost surely, 21313563453439 is an apocalyptic number.
1313563453439 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313563453439 is an equidigital number, since it uses as much as digits as its factorization.
1313563453439 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5248800, while the sum is 50.
The spelling of 1313563453439 in words is "one trillion, three hundred thirteen billion, five hundred sixty-three million, four hundred fifty-three thousand, four hundred thirty-nine".
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