Base | Representation |
---|---|
bin | 10011000111011001111… |
… | …000101000000000110111 |
3 | 11122120200110202211010011 |
4 | 103013121320220000313 |
5 | 133010243323300421 |
6 | 2443245142441051 |
7 | 163622512142206 |
oct | 23073170500067 |
9 | 4576613684104 |
10 | 1313620525111 |
11 | 4671155a4314 |
12 | 192708a33187 |
13 | 96b48c0015b |
14 | 478184c123d |
15 | 24284a9b4e1 |
hex | 131d9e28037 |
1313620525111 has 2 divisors, whose sum is σ = 1313620525112. Its totient is φ = 1313620525110.
The previous prime is 1313620525099. The next prime is 1313620525141. The reversal of 1313620525111 is 1115250263131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1313620525111 - 211 = 1313620523063 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1313620525141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656810262555 + 656810262556.
It is an arithmetic number, because the mean of its divisors is an integer number (656810262556).
Almost surely, 21313620525111 is an apocalyptic number.
1313620525111 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313620525111 is an equidigital number, since it uses as much as digits as its factorization.
1313620525111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5400, while the sum is 31.
Adding to 1313620525111 its reverse (1115250263131), we get a palindrome (2428870788242).
The spelling of 1313620525111 in words is "one trillion, three hundred thirteen billion, six hundred twenty million, five hundred twenty-five thousand, one hundred eleven".
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