13136232540 has 192 divisors, whose sum is σ = 39872448000. Its totient is φ = 3220632576.

The previous prime is 13136232539. The next prime is 13136232541. The reversal of 13136232540 is 4523263131.

It is an interprime number because it is at equal distance from previous prime (13136232539) and next prime (13136232541).

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a junction number, because it is equal to n+sod(n) for n = 13136232498 and 13136232507.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13136232541) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 8479686 + ... + 8481234.

It is an arithmetic number, because the mean of its divisors is an integer number (207669000).

Almost surely, 2^13136232540 is an apocalyptic number.

13136232540 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13136232540, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19936224000).

13136232540 is an abundant number, since it is smaller than the sum of its proper divisors (26736215460).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13136232540 is a wasteful number, since it uses less digits than its factorization.

13136232540 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1796 (or 1794 counting only the distinct ones).

The product of its (nonzero) digits is 12960, while the sum is 30.

Adding to 13136232540 its reverse (4523263131), we get a palindrome (17659495671).

The spelling of 13136232540 in words is "thirteen billion, one hundred thirty-six million, two hundred thirty-two thousand, five hundred forty".