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13136253244019 is a prime number
BaseRepresentation
bin1011111100101000010110…
…1101010101001001110011
31201111210222002000111001122
42333022011231111021303
53210211021312302034
643534413400252455
72524030413150023
oct277120555251163
951453862014048
1013136253244019
114205065549694
121581a8877112b
13743988235b29
14335b25bc1a83
1517ba864a862e
hexbf285b55273

13136253244019 has 2 divisors, whose sum is σ = 13136253244020. Its totient is φ = 13136253244018.

The previous prime is 13136253243989. The next prime is 13136253244021. The reversal of 13136253244019 is 91044235263131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13136253244019 - 216 = 13136253178483 is a prime.

It is a super-2 number, since 2×131362532440192 (a number of 27 digits) contains 22 as substring.

Together with 13136253244021, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13136253244069) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6568126622009 + 6568126622010.

It is an arithmetic number, because the mean of its divisors is an integer number (6568126622010).

Almost surely, 213136253244019 is an apocalyptic number.

13136253244019 is a deficient number, since it is larger than the sum of its proper divisors (1).

13136253244019 is an equidigital number, since it uses as much as digits as its factorization.

13136253244019 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 466560, while the sum is 44.

The spelling of 13136253244019 in words is "thirteen trillion, one hundred thirty-six billion, two hundred fifty-three million, two hundred forty-four thousand, nineteen".