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131365433 is a prime number
BaseRepresentation
bin1111101010001…
…11101000111001
3100011012001111102
413311013220321
5232112143213
621011341145
73153405413
oct765075071
9304161442
10131365433
1168174881
1237bb17b5
13212a6134
14136379b3
15b7ed158
hex7d47a39

131365433 has 2 divisors, whose sum is σ = 131365434. Its totient is φ = 131365432.

The previous prime is 131365417. The next prime is 131365439. The reversal of 131365433 is 334563131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 100540729 + 30824704 = 10027^2 + 5552^2 .

It is a cyclic number.

It is not a de Polignac number, because 131365433 - 24 = 131365417 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131365396 and 131365405.

It is not a weakly prime, because it can be changed into another prime (131365439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65682716 + 65682717.

It is an arithmetic number, because the mean of its divisors is an integer number (65682717).

Almost surely, 2131365433 is an apocalyptic number.

It is an amenable number.

131365433 is a deficient number, since it is larger than the sum of its proper divisors (1).

131365433 is an equidigital number, since it uses as much as digits as its factorization.

131365433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 9720, while the sum is 29.

The square root of 131365433 is about 11461.4760393241. The cubic root of 131365433 is about 508.3471197432.

The spelling of 131365433 in words is "one hundred thirty-one million, three hundred sixty-five thousand, four hundred thirty-three".