131365439 has 2 divisors, whose sum is σ = 131365440. Its totient is φ = 131365438.

The previous prime is 131365433. The next prime is 131365441. The reversal of 131365439 is 934563131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131365439 - 2¹² = 131361343 is a prime.

Together with 131365441, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 131365399 and 131365408.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131365433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65682719 + 65682720.

It is an arithmetic number, because the mean of its divisors is an integer number (65682720).

Almost surely, 2^131365439 is an apocalyptic number.

131365439 is a deficient number, since it is larger than the sum of its proper divisors (1).

131365439 is an equidigital number, since it uses as much as digits as its factorization.

131365439 is an evil number, because the sum of its binary digits is even.

The product of its digits is 29160, while the sum is 35.

The square root of 131365439 is about 11461.4763010705. The cubic root of 131365439 is about 508.3471274826.

The spelling of 131365439 in words is "one hundred thirty-one million, three hundred sixty-five thousand, four hundred thirty-nine".