Base | Representation |
---|---|
bin | 111101001011000011… |
… | …0001010101001001101 |
3 | 110120002012121002202221 |
4 | 1322112012022221031 |
5 | 4123020001431431 |
6 | 140203235215341 |
7 | 12330254632624 |
oct | 1722606125115 |
9 | 416065532687 |
10 | 131367217741 |
11 | 50792408051 |
12 | 21562747551 |
13 | c507215b06 |
14 | 6502cc66bb |
15 | 363cdd0111 |
hex | 1e9618aa4d |
131367217741 has 2 divisors, whose sum is σ = 131367217742. Its totient is φ = 131367217740.
The previous prime is 131367217669. The next prime is 131367217757. The reversal of 131367217741 is 147712763131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 113993341641 + 17373876100 = 337629^2 + 131810^2 .
It is a cyclic number.
It is not a de Polignac number, because 131367217741 - 221 = 131365120589 is a prime.
It is a super-2 number, since 2×1313672177412 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131367817741) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65683608870 + 65683608871.
It is an arithmetic number, because the mean of its divisors is an integer number (65683608871).
Almost surely, 2131367217741 is an apocalyptic number.
It is an amenable number.
131367217741 is a deficient number, since it is larger than the sum of its proper divisors (1).
131367217741 is an equidigital number, since it uses as much as digits as its factorization.
131367217741 is an evil number, because the sum of its binary digits is even.
The product of its digits is 148176, while the sum is 43.
The spelling of 131367217741 in words is "one hundred thirty-one billion, three hundred sixty-seven million, two hundred seventeen thousand, seven hundred forty-one".
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