Base | Representation |
---|---|
bin | 111101001011010100… |
… | …0000110101001101011 |
3 | 110120002211100002112111 |
4 | 1322112220012221223 |
5 | 4123024241124113 |
6 | 140204154023151 |
7 | 12330423355231 |
oct | 1722650065153 |
9 | 416084302474 |
10 | 131376114283 |
11 | 50797434167 |
12 | 21565717ab7 |
13 | c50900c33b |
14 | 6504160951 |
15 | 363da8b13d |
hex | 1e96a06a6b |
131376114283 has 2 divisors, whose sum is σ = 131376114284. Its totient is φ = 131376114282.
The previous prime is 131376114281. The next prime is 131376114293. The reversal of 131376114283 is 382411673131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131376114283 - 21 = 131376114281 is a prime.
Together with 131376114281, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (131376114281) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65688057141 + 65688057142.
It is an arithmetic number, because the mean of its divisors is an integer number (65688057142).
Almost surely, 2131376114283 is an apocalyptic number.
131376114283 is a deficient number, since it is larger than the sum of its proper divisors (1).
131376114283 is an equidigital number, since it uses as much as digits as its factorization.
131376114283 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 72576, while the sum is 40.
The spelling of 131376114283 in words is "one hundred thirty-one billion, three hundred seventy-six million, one hundred fourteen thousand, two hundred eighty-three".
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