Base | Representation |
---|---|
bin | 1011111100101111110111… |
… | …0001101111100010101111 |
3 | 1201112000011110111202100122 |
4 | 2333023331301233202233 |
5 | 3210224133010312412 |
6 | 43535345320315155 |
7 | 2524131343361126 |
oct | 277137561574257 |
9 | 51460143452318 |
10 | 13138267666607 |
11 | 42059a9647146 |
12 | 158234b312abb |
13 | 743c1968ca65 |
14 | 335c77552abd |
15 | 17bb53269572 |
hex | bf2fdc6f8af |
13138267666607 has 2 divisors, whose sum is σ = 13138267666608. Its totient is φ = 13138267666606.
The previous prime is 13138267666571. The next prime is 13138267666627. The reversal of 13138267666607 is 70666676283131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13138267666607 - 28 = 13138267666351 is a prime.
It is a super-2 number, since 2×131382676666072 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13138267666607.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13138267666627) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6569133833303 + 6569133833304.
It is an arithmetic number, because the mean of its divisors is an integer number (6569133833304).
Almost surely, 213138267666607 is an apocalyptic number.
13138267666607 is a deficient number, since it is larger than the sum of its proper divisors (1).
13138267666607 is an equidigital number, since it uses as much as digits as its factorization.
13138267666607 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54867456, while the sum is 62.
The spelling of 13138267666607 in words is "thirteen trillion, one hundred thirty-eight billion, two hundred sixty-seven million, six hundred sixty-six thousand, six hundred seven".
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