Base | Representation |
---|---|
bin | 111101001011100010… |
… | …0101111011101011111 |
3 | 110120010100110111110111 |
4 | 1322113010233131133 |
5 | 4123033201341341 |
6 | 140205022550451 |
7 | 12330544233124 |
oct | 1722704573537 |
9 | 416110414414 |
10 | 131383621471 |
11 | 507a06a1453 |
12 | 21568138427 |
13 | c50a73a36b |
14 | 650515674b |
15 | 363e570681 |
hex | 1e9712f75f |
131383621471 has 2 divisors, whose sum is σ = 131383621472. Its totient is φ = 131383621470.
The previous prime is 131383621429. The next prime is 131383621483. The reversal of 131383621471 is 174126383131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131383621471 - 29 = 131383620959 is a prime.
It is a super-3 number, since 3×1313836214713 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131383621871) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65691810735 + 65691810736.
It is an arithmetic number, because the mean of its divisors is an integer number (65691810736).
Almost surely, 2131383621471 is an apocalyptic number.
131383621471 is a deficient number, since it is larger than the sum of its proper divisors (1).
131383621471 is an equidigital number, since it uses as much as digits as its factorization.
131383621471 is an evil number, because the sum of its binary digits is even.
The product of its digits is 72576, while the sum is 40.
The spelling of 131383621471 in words is "one hundred thirty-one billion, three hundred eighty-three million, six hundred twenty-one thousand, four hundred seventy-one".
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