Base | Representation |
---|---|
bin | 111101001100000001… |
… | …1001001001110111111 |
3 | 110120011111020121002201 |
4 | 1322120003021032333 |
5 | 4123101343324332 |
6 | 140210405332331 |
7 | 12331133254414 |
oct | 1723003111677 |
9 | 416144217081 |
10 | 131399979967 |
11 | 507a9954873 |
12 | 215717070a7 |
13 | c510c47149 |
14 | 65073b410b |
15 | 3640c025e7 |
hex | 1e980c93bf |
131399979967 has 2 divisors, whose sum is σ = 131399979968. Its totient is φ = 131399979966.
The previous prime is 131399979959. The next prime is 131399979989. The reversal of 131399979967 is 769979993131.
It is a weak prime.
It is an emirp because it is prime and its reverse (769979993131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131399979967 - 23 = 131399979959 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 131399979967.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131397979967) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65699989983 + 65699989984.
It is an arithmetic number, because the mean of its divisors is an integer number (65699989984).
Almost surely, 2131399979967 is an apocalyptic number.
131399979967 is a deficient number, since it is larger than the sum of its proper divisors (1).
131399979967 is an equidigital number, since it uses as much as digits as its factorization.
131399979967 is an evil number, because the sum of its binary digits is even.
The product of its digits is 156243654, while the sum is 73.
The spelling of 131399979967 in words is "one hundred thirty-one billion, three hundred ninety-nine million, nine hundred seventy-nine thousand, nine hundred sixty-seven".
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