131400031421455 has 32 divisors (see below), whose sum is σ = 166245353208000. Its totient is φ = 99427610161152.

The previous prime is 131400031421411. The next prime is 131400031421521. The reversal of 131400031421455 is 554124130004131.

It is a cyclic number.

It is not a de Polignac number, because 131400031421455 - 2¹³ = 131400031413263 is a prime.

It is a super-2 number, since 2×131400031421455² (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 131400031421455.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 520375071 + ... + 520627519.

It is an arithmetic number, because the mean of its divisors is an integer number (5195167287750).

Almost surely, 2^{131400031421455} is an apocalyptic number.

131400031421455 is a deficient number, since it is larger than the sum of its proper divisors (34845321786545).

131400031421455 is a wasteful number, since it uses less digits than its factorization.

131400031421455 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 261243.

The product of its (nonzero) digits is 28800, while the sum is 34.

Adding to 131400031421455 its reverse (554124130004131), we get a palindrome (685524161425586).

The spelling of 131400031421455 in words is "one hundred thirty-one trillion, four hundred billion, thirty-one million, four hundred twenty-one thousand, four hundred fifty-five".