Base | Representation |
---|---|
bin | 111101001100000001… |
… | …1101011011110110011 |
3 | 110120011111111201112010 |
4 | 1322120003223132303 |
5 | 4123101412321433 |
6 | 140210412334003 |
7 | 12331134410400 |
oct | 1723003533663 |
9 | 416144451463 |
10 | 131400120243 |
11 | 507a9a401a7 |
12 | 21571774303 |
13 | c510c95c52 |
14 | 650740d2a7 |
15 | 3640c2de63 |
hex | 1e980eb7b3 |
131400120243 has 48 divisors (see below), whose sum is σ = 205632725760. Its totient is φ = 74413684800.
The previous prime is 131400120239. The next prime is 131400120317. The reversal of 131400120243 is 342021004131.
It is not a de Polignac number, because 131400120243 - 22 = 131400120239 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is not an unprimeable number, because it can be changed into a prime (131400120443) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 15959938 + ... + 15968168.
It is an arithmetic number, because the mean of its divisors is an integer number (4284015120).
Almost surely, 2131400120243 is an apocalyptic number.
131400120243 is a deficient number, since it is larger than the sum of its proper divisors (74232605517).
131400120243 is a wasteful number, since it uses less digits than its factorization.
131400120243 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9208 (or 9201 counting only the distinct ones).
The product of its (nonzero) digits is 576, while the sum is 21.
Adding to 131400120243 its reverse (342021004131), we get a palindrome (473421124374).
The spelling of 131400120243 in words is "one hundred thirty-one billion, four hundred million, one hundred twenty thousand, two hundred forty-three".
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