Base | Representation |
---|---|
bin | 11101111000001000000000… |
… | …010010010000110001001111 |
3 | 122020020201222020202202122002 |
4 | 131320020000102100301033 |
5 | 114210330134431203403 |
6 | 1143244233445142515 |
7 | 36451232204320262 |
oct | 3570100022206117 |
9 | 566221866682562 |
10 | 131400234241103 |
11 | 389605876a5303 |
12 | 128a22b46baa3b |
13 | 5841cb1874859 |
14 | 2463b3b940cd9 |
15 | 102d04d078188 |
hex | 778200490c4f |
131400234241103 has 2 divisors, whose sum is σ = 131400234241104. Its totient is φ = 131400234241102.
The previous prime is 131400234241093. The next prime is 131400234241123. The reversal of 131400234241103 is 301142432004131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131400234241103 - 212 = 131400234237007 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131400234241123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65700117120551 + 65700117120552.
It is an arithmetic number, because the mean of its divisors is an integer number (65700117120552).
Almost surely, 2131400234241103 is an apocalyptic number.
131400234241103 is a deficient number, since it is larger than the sum of its proper divisors (1).
131400234241103 is an equidigital number, since it uses as much as digits as its factorization.
131400234241103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 131400234241103 its reverse (301142432004131), we get a palindrome (432542666245234).
The spelling of 131400234241103 in words is "one hundred thirty-one trillion, four hundred billion, two hundred thirty-four million, two hundred forty-one thousand, one hundred three".
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