Base | Representation |
---|---|
bin | 1011111100110110100010… |
… | …1001000011100010000101 |
3 | 1201112011210102010201210110 |
4 | 2333031220221003202011 |
5 | 3210241321000120201 |
6 | 43540243244143233 |
7 | 2524223643552165 |
oct | 277155051034205 |
9 | 51464712121713 |
10 | 13140060551301 |
11 | 4206739690a32 |
12 | 158276b837b19 |
13 | 744143c5b288 |
14 | 335da76d65a5 |
15 | 17bc0a8696d6 |
hex | bf368a43885 |
13140060551301 has 32 divisors (see below), whose sum is σ = 18561250470400. Its totient is φ = 8245417602240.
The previous prime is 13140060551273. The next prime is 13140060551311. The reversal of 13140060551301 is 10315506004131.
It is not a de Polignac number, because 13140060551301 - 222 = 13140056356997 is a prime.
It is a super-2 number, since 2×131400605513012 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13140060551311) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 116092506 + ... + 116205636.
It is an arithmetic number, because the mean of its divisors is an integer number (580039077200).
Almost surely, 213140060551301 is an apocalyptic number.
It is an amenable number.
13140060551301 is a deficient number, since it is larger than the sum of its proper divisors (5421189919099).
13140060551301 is a wasteful number, since it uses less digits than its factorization.
13140060551301 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 126289.
The product of its (nonzero) digits is 5400, while the sum is 30.
Adding to 13140060551301 its reverse (10315506004131), we get a palindrome (23455566555432).
The spelling of 13140060551301 in words is "thirteen trillion, one hundred forty billion, sixty million, five hundred fifty-one thousand, three hundred one".
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