131401222420432 has 10 divisors (see below), whose sum is σ = 254589868439618. Its totient is φ = 65700611210208.

The previous prime is 131401222420421. The next prime is 131401222420439. The reversal of 131401222420432 is 234024222104131.

It can be written as a sum of positive squares in only one way, i.e., 125732804268096 + 5668418152336 = 11213064^2 + 2380844^2 .

It is a junction number, because it is equal to n+sod(n) for n = 131401222420394 and 131401222420403.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131401222420439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4106288200623 + ... + 4106288200654.

Almost surely, 2^{131401222420432} is an apocalyptic number.

It is an amenable number.

131401222420432 is a deficient number, since it is larger than the sum of its proper divisors (123188646019186).

131401222420432 is an equidigital number, since it uses as much as digits as its factorization.

131401222420432 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8212576401285 (or 8212576401279 counting only the distinct ones).

The product of its (nonzero) digits is 18432, while the sum is 31.

Adding to 131401222420432 its reverse (234024222104131), we get a palindrome (365425444524563).

The spelling of 131401222420432 in words is "one hundred thirty-one trillion, four hundred one billion, two hundred twenty-two million, four hundred twenty thousand, four hundred thirty-two".