Base | Representation |
---|---|
bin | 111101001100000100… |
… | …0010010001111101101 |
3 | 110120011120210001200221 |
4 | 1322120020102033231 |
5 | 4123102214440342 |
6 | 140210454251341 |
7 | 12331150566361 |
oct | 1723010221755 |
9 | 416146701627 |
10 | 131401327597 |
11 | 507aa695311 |
12 | 21572056b51 |
13 | c5112c9667 |
14 | 65076452a1 |
15 | 3640dbba67 |
hex | 1e982123ed |
131401327597 has 2 divisors, whose sum is σ = 131401327598. Its totient is φ = 131401327596.
The previous prime is 131401327583. The next prime is 131401327601. The reversal of 131401327597 is 795723104131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 74499518916 + 56901808681 = 272946^2 + 238541^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131401327597 is a prime.
It is a super-2 number, since 2×1314013275972 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131401327537) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65700663798 + 65700663799.
It is an arithmetic number, because the mean of its divisors is an integer number (65700663799).
Almost surely, 2131401327597 is an apocalyptic number.
It is an amenable number.
131401327597 is a deficient number, since it is larger than the sum of its proper divisors (1).
131401327597 is an equidigital number, since it uses as much as digits as its factorization.
131401327597 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 158760, while the sum is 43.
The spelling of 131401327597 in words is "one hundred thirty-one billion, four hundred one million, three hundred twenty-seven thousand, five hundred ninety-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •