1314013401232 has 80 divisors (see below), whose sum is σ = 3003931164672. Its totient is φ = 544896881280.

The previous prime is 1314013401221. The next prime is 1314013401257. The reversal of 1314013401232 is 2321043104131.

It is a junction number, because it is equal to n+sod(n) for n = 1314013401197 and 1314013401206.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 25135473 + ... + 25187695.

Almost surely, 2^{1314013401232} is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1314013401232, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1501965582336).

1314013401232 is an abundant number, since it is smaller than the sum of its proper divisors (1689917763440).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1314013401232 is a wasteful number, since it uses less digits than its factorization.

1314013401232 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 59516 (or 59510 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1314013401232 its reverse (2321043104131), we get a palindrome (3635056505363).

The spelling of 1314013401232 in words is "one trillion, three hundred fourteen billion, thirteen million, four hundred one thousand, two hundred thirty-two".