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13140142153 is a prime number
BaseRepresentation
bin11000011110011011…
…01010100001001001
31020220202111101100121
430033031222201021
5203402334022103
610011514503241
7643424236225
oct141715524111
936822441317
1013140142153
1156332a4316
122668734b21
13131542b958
148c9209785
1551d8d56bd
hex30f36a849

13140142153 has 2 divisors, whose sum is σ = 13140142154. Its totient is φ = 13140142152.

The previous prime is 13140142091. The next prime is 13140142207. The reversal of 13140142153 is 35124104131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12023780409 + 1116361744 = 109653^2 + 33412^2 .

It is a cyclic number.

It is not a de Polignac number, because 13140142153 - 221 = 13138045001 is a prime.

It is not a weakly prime, because it can be changed into another prime (13140142753) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570071076 + 6570071077.

It is an arithmetic number, because the mean of its divisors is an integer number (6570071077).

Almost surely, 213140142153 is an apocalyptic number.

It is an amenable number.

13140142153 is a deficient number, since it is larger than the sum of its proper divisors (1).

13140142153 is an equidigital number, since it uses as much as digits as its factorization.

13140142153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 13140142153 its reverse (35124104131), we get a palindrome (48264246284).

The spelling of 13140142153 in words is "thirteen billion, one hundred forty million, one hundred forty-two thousand, one hundred fifty-three".