Base | Representation |
---|---|
bin | 11000011110011011… |
… | …01010100001001001 |
3 | 1020220202111101100121 |
4 | 30033031222201021 |
5 | 203402334022103 |
6 | 10011514503241 |
7 | 643424236225 |
oct | 141715524111 |
9 | 36822441317 |
10 | 13140142153 |
11 | 56332a4316 |
12 | 2668734b21 |
13 | 131542b958 |
14 | 8c9209785 |
15 | 51d8d56bd |
hex | 30f36a849 |
13140142153 has 2 divisors, whose sum is σ = 13140142154. Its totient is φ = 13140142152.
The previous prime is 13140142091. The next prime is 13140142207. The reversal of 13140142153 is 35124104131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12023780409 + 1116361744 = 109653^2 + 33412^2 .
It is a cyclic number.
It is not a de Polignac number, because 13140142153 - 221 = 13138045001 is a prime.
It is not a weakly prime, because it can be changed into another prime (13140142753) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570071076 + 6570071077.
It is an arithmetic number, because the mean of its divisors is an integer number (6570071077).
Almost surely, 213140142153 is an apocalyptic number.
It is an amenable number.
13140142153 is a deficient number, since it is larger than the sum of its proper divisors (1).
13140142153 is an equidigital number, since it uses as much as digits as its factorization.
13140142153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 13140142153 its reverse (35124104131), we get a palindrome (48264246284).
The spelling of 13140142153 in words is "thirteen billion, one hundred forty million, one hundred forty-two thousand, one hundred fifty-three".
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