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13140210023 = 53353702347
BaseRepresentation
bin11000011110011011…
…11011000101100111
31020220202121211110022
430033031323011213
5203402343210043
610011520145355
7643424641133
oct141715730547
936822554408
1013140210023
115633340306
12266876825b
131315453805
148c92263c3
1551d8ea868
hex30f37b167

13140210023 has 8 divisors (see below), whose sum is σ = 13426084368. Its totient is φ = 12855741184.

The previous prime is 13140209987. The next prime is 13140210037. The reversal of 13140210023 is 32001204131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13140210023 - 216 = 13140144487 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13140209983 and 13140210010.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13140210073) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 332465 + ... + 369882.

It is an arithmetic number, because the mean of its divisors is an integer number (1678260546).

Almost surely, 213140210023 is an apocalyptic number.

13140210023 is a deficient number, since it is larger than the sum of its proper divisors (285874345).

13140210023 is an equidigital number, since it uses as much as digits as its factorization.

13140210023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 702753.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 13140210023 its reverse (32001204131), we get a palindrome (45141414154).

The spelling of 13140210023 in words is "thirteen billion, one hundred forty million, two hundred ten thousand, twenty-three".

Divisors: 1 53 353 18709 702347 37224391 247928491 13140210023